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#1




A math question: fitting a square into a circle
I swear to Cecil I have not been in school for 8 years, so this isn't a homework question, I just have a personal little project that I'm too dumb for.
How do you figure out the measurement for the side of a square if you know the measurement for the diagonal? (The square's gotta fit inside a circle, the points at the corners of the square rest on the circle, so I figure the diagonal of the square is equal to the diameter of the circle right?) 
#2




It's the square root of two times the radius of the circle.

#3




When you have a square divided by a diagonal, you have two equilateral right triangles.
Remember the Pythagorean Theorem? a^{2} + b^{2} = c^{2}. In this case, a=b, and you know c (the length of the diagonal). So, 2a^{2} = c^{2}, where a=the length of the side, and c=the length of the diagonal. 
#4




Oops.



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#6




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O.K. so the diameter of the circle / diagonal of the square is 4.75" squared is: 22.5625" half of which is equal to a^{2}, right? So a^{2} is 11.28125" and then a = 3.358757yadda yadda yadda (for my purposes 3 1/3 is o.k.) Am I correct? 
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#8




Thanks, all!

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